Answer:
pH = 6.80. The aqueous solution is slightly acid
If pH is 7.00 at 37°C, solution is neutral
Explanation:
2H₂O ⇄ H₃O⁺ + OH⁻ Kw = 2.4×10⁻¹⁴
To determine the pH of a solution, we must consider the [H₃O⁺]
[H₃O⁺] . [OH⁻] = 2.4×10⁻¹⁴
[H₃O⁺] = [OH⁻] → √2.4×10⁻¹⁴ = [H₃O⁺]
1.55×10⁻⁷ = [H₃O⁺]
pH = - log 1.55×10⁻⁷ = 6.80
pH = 7 → neutral
pH < 7 → acid
pH > 7→ basic
