Answer:
[tex]O_{2}[/tex] to form [tex]H_{2}O[/tex]
Explanation:
The electrons start their journey through metabolism in [tex]H_{2}O[/tex] and end in the [tex]H_{2}O[/tex] that is made. [tex]O_{2}[/tex] serves as the final electron acceptor in oxidative phosphorylation, so as to combine with protons to make new "metabolic" water.