Answer:
c. 40
Explanation:
Given that:
The mean temperature for each day during May and June is = 70°F ; &
a base temperature = 40°F
Then the average temperature difference = 70°F - 40°F
= 30°F
That means the pea accumulate 30 growing degrees per day.
NOW, If the peas need 1200 growing degree days and accumulate 30 per day, then they will need 40 days before they are harvested
(i.e [tex]\frac{1200}{30}[/tex] = 40)
Hence, if the pea plants are planted in Indiana on May 1, the peas will be ready on June 10.
The number of days required by peas to be ready to pick has been 40 days. Thus, option C is correct.
The temperature needed by peas to grow has been given as, [tex]T_f=70\;^\circ\rm F[/tex]. The base temperature has been, [tex]T_b=40\;^\circ \rm F[/tex]. The difference in temperature has been given by:
[tex]T=T_f-T_b[/tex]
Substituting the values for temperature, T:
[tex]T=70-40\;^\circ \rm F\\\textit T=30\;^\circ \rm F\\[/tex]
Thus, the temperature acquired by peas has been 30 growing degree days.
Since at [tex]70\;^\circ\rm F[/tex], the days required has been given as:
[tex]\rm Days=\dfrac{1200}{30}\\Days=40[/tex]
The number of days required by peas to be ready to pick has been 40 days. Thus, option C is correct.
For more information about pea plant, refer to the link:
https://brainly.com/question/289178
