Answer: The number of revolutions required to level the park is 100.
Step-by-step explanation:
Given : Diameter of roller = 77 cm
Then radius of roller : r = [tex]\dfrac{77}{2}\ cm[/tex]
Height = 1 m = 100 cm
Curved surface area of roller = [tex]2\pi rh= 2\times\dfrac{22}{7}\times\dfrac{77}{2}\times100=24200\ cm^2[/tex]
Dimensions of park = 22 × 11 m
Then Area of park = [tex]22\times11\ m^2= 232\ m^2=232\times100\times100 \ cm^2[/tex]
[tex]=2420000\ cm^2[/tex]
Now , the number of revolutions required to level the park = (Area of park) ÷ (Curved surface area of roller )
[tex]2420000\div 24200=100[/tex]
Hence, the number of revolutions required to level the park is 100.
