Respuesta :
Answer:
211.2 N
Explanation:
Data provided in the question:
Mass of child, m = 33.0 kg
Distance from the center, r = 2.50 m
Tangential speed, v = 4.00 m/s
Now,
Magnitude of the centripetal force, [tex]F_c = \frac{mv^2}{r}[/tex]
Thus, on putting the values, we get
Magnitude of the centripetal force, [tex]F_c = \frac{33\times4^2}{2.50}[/tex]
or
Magnitude of the centripetal force, [tex]F_c[/tex] = 211.2 N
Answer:
[tex]F=211.2\ N[/tex]
Explanation:
Given:
- mass of the child, [tex]m=33\ kg[/tex]
- radial distance of the child, [tex]r=2.5\ m[/tex]
- tangential speed of the child, [tex]v_t=4\ m.s^{-1}[/tex]
Now from the given data we find the centrifugal force acting on the child mass:
[tex]F=m.\frac{v_t^2}{r}[/tex]
[tex]F=33\times \frac{4^2}{2.5}[/tex]
[tex]F=211.2\ N[/tex]
- So for the child to be in state of equilibrium with respect to the merry-go-round an equal amount of centripetal force must be acting on the child to keep it stationary with respect to the merry-go-round.
- Do note that a centrifugal force always acts away from the center of rotation and a centrifugal force always acts towards the center of rotation.
