Step-by-step explanation:
[tex]y = 2x - 7...(1) \\ y = 5x + 4...(2) \\ from \: equations \: (1) \: and \: (2) \\ 5x + 4 = 2x - 7 \\ \therefore \: 5x - 2x = - 7 - 4 \\ \therefore \: 3x = - 11\\ \huge \red{ \boxed{\therefore \: x = - \frac{11}{3} }}\\ substitutig \: x = - \frac{11}{3} in \: equation \: (1) \\ y = 2 \times (- \frac{11}{3}) - 7 \\ \\ \therefore \: y = - \frac{22}{3} - 7 \\ \\ \therefore \: y = \frac{ - 22 - 21}{3} \\ \\ \huge \orange{ \boxed{\therefore \: y = - \frac{ 43}{3}}}\\\\
(x, \:y) = \{- \frac{11}{3}, - \frac{ 43}{3}\} \: [/tex]
