Rearranging literal equations ASAP REALLY NEED HELP PLEASE

Answer:
q = [tex]\frac{-2}{5}[/tex]
Step-by-step explanation:
(i) [tex](\frac{-6p + 10q}{10q - 1})^{ \frac{1}{3} }[/tex] = 2
Cubing we get
[tex]\frac{-6p + 10q}{10q - 1} = 2^{3}[/tex]
-6p + 10q = 80q - 8
-6p + 8 = 70q
[tex]q = \frac{-6p + 8}{70}[/tex]
(ii) If p = 6 then
q = [tex]\frac{-28}{70}[/tex] = [tex]\frac{-2}{5}[/tex]