Respuesta :
Answer:
0.0003 m = 0.3 mm
Explanation:
For constructive interference in the Young's experiment.
The position of the mth fringe from the central fringe is given by
y = L(mλ/d)
λ = wavelength = 720 nm = 720 × 10⁻⁹ m
L = distance between slits and screen respectively = 1.0 m
d = separation of slits = 0.68 mm = 0.68 × 10⁻³ m
m = 2
y = 1(2 × 720 × 10⁻⁹/(0.68 × 10⁻³) = 0.00212 m = 2.12 mm
For the 620 nm light,
y = 1(2 × 620 × 10⁻⁹/(0.68 × 10⁻³) = 0.00182 m = 1.82 mm
Distance apart = 2.12 - 1.82 = 0.3 mm = 0.0003 m
The distance apart should be 0.0003 m = 0.3 mm
Calculation of the distance apart:
Since
The position of the mth fringe from the central fringe is provided by
y = L(mλ/d)
Here,
λ = wavelength = 720 nm = 720 × 10⁻⁹ m
L = distance between slits and screen respectively = 1.0 m
d = separation of slits = 0.68 mm = 0.68 × 10⁻³ m
m = 2
So,
y = 1(2 × 720 × 10⁻⁹/(0.68 × 10⁻³) = 0.00212 m = 2.12 mm
Now For the 620 nm light,
y = 1(2 × 620 × 10⁻⁹/(0.68 × 10⁻³) = 0.00182 m = 1.82 mm
Now finally
Distance apart should be
= 2.12 - 1.82
= 0.3 mm
= 0.0003 m
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