Respuesta :
Answer : The current passing between the electrodes is, [tex]1.056\times 10^{-2}A[/tex]
Explanation :
First we have to calculate the charge of sodium ion.
[tex]q=ne[/tex]
where,
q = charge of sodium ion
n = number of sodium ion = [tex]2.68\times 10^{16}[/tex]
e = charge on electron = [tex]1.6\times 10^{-19}C[/tex]
Now put all the given values in the above formula, we get:
[tex]q=(2.68\times 10^{16})\times (1.6\times 10^{-19}C)=4.288\times 10^{-3}C[/tex]
Now we have to calculate the charge of chlorine ion.
[tex]q'=ne[/tex]
where,
q' = charge of chlorine ion
n = number of chlorine ion = [tex]3.92\times 10^{16}[/tex]
e = charge on electron = [tex]1.6\times 10^{-19}C[/tex]
Now put all the given values in the above formula, we get:
[tex]q'=(3.92\times 10^{16})\times (1.6\times 10^{-19}C)=6.272\times 10^{-3}C[/tex]
Now we have to calculate the current passing between the electrodes.
[tex]I=\frac{q}{t}+\frac{q'}{t}[/tex]
[tex]I=\frac{4.288\times 10^{-3}}{1.00}+\frac{6.272\times 10^{-3}}{1.00}[/tex]
[tex]I=1.056\times 10^{-2}A[/tex]
Thus, the current passing between the electrodes is, [tex]1.056\times 10^{-2}A[/tex]
