The ph after the following volumes of acid have been added is mathematically given as
pH=1.82
What is the ph value?
Question Parameters:
A 20.0-ml sample of 0.150 m koh is titrated with 0.125 m hclo4 solution.
Generally, the equation for the Chemical Reaction is mathematically given as
HClO4+KOH--->KClO4+H20
Therefore
3.0*10^{-3} mole of HClO4[H+] will react with 3.0*10^{-3}[oH-] moles of KOH
Hence excess HClO4 is
x=(3.75*10^{-3} 3.0*10^{-3}}
x=0.75*10^{-3}
The final volume is
V=20+30
V=50*10^{-3}
In conclusion, The pH value is
pH = - log [H3O+].
Hence
pH=1.82
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