Answer:
A = -0.576 μC
B = 4.256 μC
Explanation:
Suppose a single electron charge is [tex]1.6\times10^{-19}C[/tex]. Then the total charge that is flowing from B to A is:
[tex]1.6\times10^{-19} * 1.51 \times 10^{13} = 2.416\times10^{-6}C = 2.416 \mu C[/tex]
Let A and B be the initial charge of spheres A and B, respectively. Since the net charge is 3.68μC we have the following equation
[tex]A + B = 3.68[/tex] (1)
When they touch 2.416μC flows from B to A, then they are equal, so we have the following equation
[tex]A + 2.416 = B - 2.416[/tex]
[tex]-A + B = 2.416 + 2.416 = 4.832 [/tex] (2)
Add equation (1) to equation (2) we have
[tex]2B = 3.68 + 4.832 = 8.512[/tex]
[tex]B = 8.512 / 2 = 4.256 \mu C[/tex]
[tex]A = 3.68 - B = 3.68 - 4.256 = -0.576 \mu C[/tex]
