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In this circuit the resistance R1 is 7 Ω and R2 is 3 Ω. If this combination of resistors were to be replaced by a single resistor with an equivalent resistance, what should that resistance be? Give your answer in units of Ohms (LaTeX: \OmegaΩ).

Respuesta :

Answer:

Series combination:

Equivalent resistance =10Ω

Parallel combination:

Equivalent resistance [tex]=\frac{21}{10} \Omega[/tex]

Explanation:

Resistance: Resistance is the ratio of voltage to the current.

[tex]R=\frac{V}{I}[/tex]

R = resistance

I = current

V= potential difference(voltage)

There are two types of resistance combinations.

  1. series combination
  2. parallel combination.

Series combination: If the ending point of one resistance is connected to the starting point of other resistance that combination is known as series combination.

If R₁,R₂ and R₃  are connected in series combination.

Then equivalent resistance = R₁+R₂+R₃

Parallel combination: If the ending point and the starting point of the all resistance are the same points that combination is known as parallel combination.

If R₁,R₂ and R₃  are connected in parallel combination.

Then equivalent resistance  [tex]\frac{1}{R}= \frac{1}{R_1}+ \frac{1}{R_2}+\frac{1}{R_3}[/tex]

Here R₁=7Ω and     R₂=3Ω

If R₁ and R₂  connected in series combination

Then equivalent resistance = (7+3) Ω

                                            =10Ω

If R₁ and R₂  connected in parallel combination

Then equivalent resistance [tex]=\frac{1}{(\frac{1}{7} +\frac{1}{3})} \Omega[/tex]

                                              [tex]=\frac{21}{10} \Omega[/tex]

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