Answer:
a) 2319.6 kPa
b) 0.027
c) 287.86 kg/m^3
Explanation:
The pressure is determined from table in the appendix for the given temperature:
P_220=2319.6 kPa
to calculate the quality we need to determine the masses of the vapor and the liquid and for that we need the respective specific volumes which can also be found in table.
m_liq = V_liq/α_liq
= 504.2 kg
m_vap = V_vap/α_vap
= 13.94 kg
q = m_vap/m_liq
= 0.027
Finally, the density is simply calculated as follows:
p = m_tot/V_tot
= 518.14 kg/1.8 m^3
= 287.86 kg/m^3
