Respuesta :
Answer:
See explanation below
Explanation:
In this case, we first need to write the general equation of the peroxide and the manganate which is:
H2O2 + KMnO4 ----> MnO2 + KOH + O2 + H2O
Now, we need to balance this. We can balance through REDOX, oxidation number or ion electron mode. Either method you use, the balanced reaction is the following:
3H2O2 + 2KMnO4 ----> 2MnO2 + 2KOH + 3O2 + 2H2O
Now that we have this, we can say that:
3 moles H2O2 = 2 moles KMnO4
moles can be expressed in terms of concentration and volume
n = M*V
Replacing this, above we have:
3 M* V H2O2 = 2 M* V KMnO4
We have volume and concentration of permanganate, and volume of peroxyde, so we can solve for the concentration:
M H2O2 = 2 * M * V KMnO4 / 3 V H2O2
Replacing the values we have:
M H2O2 = 2 * 0.195 * 22.25 / 3 * 10
M H2O2 = 0.283 M
