Answer:
4m
Explanation:
Using the kinematic equation;
For the first stage when the car is initially moving at 0.5m/s
definitely u = 0.5 m/s and v = 0
The cart comes to rest after traveling I m, ∴ (s) = 1m
the acceleration of the car can be expressed by applying the kinematic equation:
[tex]v^2-u^2=2as[/tex]
making "a" the subject of the formula; we have:
[tex]a = \frac{v^2-u^2}{2s}[/tex]
[tex]a= \frac{0-(0.5 m/s)^2}{2(1m)}[/tex]
a = 0.125 m/s²
The experiment is repeated on the same track, but now the cart is initially moving at I m/s
i.e v = 1 m/s and u=0
[tex]S=\frac{v^2-u^2}{2a}[/tex]
[tex]S= \frac{(1m/s)^2-0}{2(0.125m/s^2)}[/tex]
S = 4 m
∴ the cart traveled 4m before coming to rest.
