The value of ΔVBA will be "2.825 V".
Given:
- A = 2 m²
- d = 5 cm or, 0.05 m
- ϵ0 = 8.85×10⁻¹² C² N⋅m²
The capacitance of the plates will be:
→ [tex]C = \frac{\epsilon_0 A}{d}[/tex]
By substituting the values,
[tex]= \frac{8.85\times 10^{-12}\times 2}{0.05}[/tex]
[tex]= 354\times 10^{-12} \ F[/tex]
hence,
→ [tex]V_{AB} = \frac{Q}{C}[/tex]
[tex]= \frac{1\times 10^{-9}}{354\times 10^{-12}}[/tex]
[tex]= 2.825 \ V[/tex]
Thus the above approach is right.
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