Respuesta :
Answer: The concentration of [tex]HNO_3[/tex] in the final solution is 0.182 M
Explanation:
To calculate the molarity of the solution after mixing 2 solutions, we use the equation:
[tex]M=\frac{n_1M_1V_1+n_2M_2V_2}{V_1+V_2}[/tex]
where,
[tex]n_1,M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of the [tex]HNO_3[/tex]
[tex]n_2,M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of the [tex]HNO_3[/tex]
We are given:
[tex]n_1=1\\M_1=0.100M\\V_1=40.0mL\\n_2=1\\M_2=0.200\\V_2=180.00mL[/tex]
Putting all the values in above equation, we get:
[tex]M=\frac{(1\times 0.100\times 40.0)+(1\times 0.200\times 180.00)}{40.0+180.00}\\\\M=0.182M[/tex]
Hence, the concentration of [tex]HNO_3[/tex] in the final solution is 0.182 M
