Respuesta :
Answer:
(a).The mass of the block of ice 87.16 kg.
(b). The distance is 24.98 m.
Explanation:
Given that,
Horizontal force = 72.0 N
Distance = 12.5 m
Time = 5.50 s
We need to calculate the acceleration
Using equation of motion
[tex]s=ut+\dfrac{1}{2}at^2[/tex]
Where, u = initial velocity
a = acceleration
t = time
s = distance
Put the value into the formula
[tex]12.5=0+\dfrac{1}{2}\times a\times(5.50)^2[/tex]
[tex]a=\dfrac{2\times12.5}{(5.50)^2}[/tex]
[tex]a=0.826\ m/s^2[/tex]
(a). We need to calculate the mass of the block of ice
Using formula of force
[tex]F=ma[/tex]
[tex]m=\dfrac{F}{a}[/tex]
Put the value into the formula
[tex]m=\dfrac{72.0}{0.826}[/tex]
[tex]m=87.16\ kg[/tex]
(b). If the worker stops pushing after 5.50 s.
We need to calculate the final velocity
Using equation of motion
[tex]v=u+at[/tex]
Put the value into the formula
[tex]v=0+0.826\times5.50[/tex]
[tex]v=4.543\ m/s[/tex]
We need to calculate the distance
Using formula of velocity
[tex]v=\dfrac{d}{t}[/tex]
[tex]d=v\times t[/tex]
Put the value into the formula
[tex]d=4.543\times5.50[/tex]
[tex]d=24.98\ m[/tex]
The distance is 24.98 m.
Hence, (a).The mass of the block of ice 87.16 kg.
(b). The distance is 24.98 m.
