Answer:
The equilibrium pressure of trans-2-butene is 0.193 atm.
Explanation:
Kp = Ptrans-2-butene/Pcis-2-butene
Kp = 3.4
Initial pressure of cis-2-butene = 0.25 atm
Let the equilibrium pressure of trans-2-butene be y
From the equation of reaction,
Mole ratio of cis-2-butene to trans-2-butene is 1:1, therefore equilibrium pressure of cis-2-butene is (0.25 - y)
3.4 = y/(0.25 - y)
y = 3.4(0.25 - y)
y = 0.85 - 3.4y
y + 3.4y = 0.85
4.4y = 0.85
y = 0.85/4.4 = 0.193 atm
