Respuesta :
Explanation:
It is known that the relation between electric field and potential is as follows.
E = [tex]\frac{V}{d}[/tex]
And, formula to calculate the capacitance is as follows.
C = [tex]\frac{\epsilon_{o} A}{d}[/tex]
= [tex]\frac{8.854 \times 10^{-12} \times (0.479 m)^{2}}{0.479 \times 10^{-3}}[/tex]
= [tex]4.24 \times 10^{-9}[/tex] F
Hence, energy stored in a capacitor is as follows.
W = [tex]\frac{1}{2}CV^{2}[/tex]
V = [tex]\sqrt{\frac{2W}{C}}[/tex]
E = [tex]\sqrt{\frac{2W}{d^{2}C}}[/tex]
= [tex]\frac{2 \times 8.11 \times 10^{-9} J}{(0.479 \times 10^{-3})^{2} \times 4.24 \times 10^{-9}}[/tex]
= [tex]16.687 \times 10^{3} N/C[/tex]
Thus, we can conclude that electric field strength E inside the capacitor is [tex]16.687 \times 10^{3} N/C[/tex].
