21.2912 moles of molten iron will be produced from 1.7 kg of Fe203.
Explanation:
From the equation:
Fe2O3(s)+2Al(s)→Al2O3(s)+2Fe(l)
it is found that 1 mole of Fe203 will undergo thermite reaction to yield 2 moles of molten iron.
The weight of Fe203 given is 1.7 kg OR 1700 Grams
The atomic weight of the Fe2O3= 159.69
Number of moles can be calculated as= 1700/159.69
= 10.64 moles of Fe2O3
So, from stochiometry,
1 mole Fe2O3 yield 2 moles of Fe
so 10.64 moles will yield x mole of Fe
2/1=x/10.64
x= 21.2912 moles
Thus, 21.2912 moles of molten iron will be produced from 1.7 kg of Fe203.