Answer:
310.94 grams of benzene.
Explanation:
Q = mL
Q is quantity of heat energy required to melt benzene = 39.8 kJ
MW of benzene (C6H6) = 78 g/mol
L = specific latent heat of fusion of benzene = molar heat of fusion × MW = 9.95 kJ/mol × 1 mol/78 g = 0.128 kJ/g
m = Q/L = 39.8 kJ/0.128 kJ/g = 310.94 g