Complete the equation for the reaction of NaHCO 3 ( s ) NaHCO3(s) with HC 2 H 3 O 2 ( aq ) HC2H3O2(aq) . Include phase symbols. NaHCO 3 ( s ) + HC 2 H 3 O 2 ( aq ) ⟶

Respuesta :

Answer:

NaHCO 3 ( s ) + HC 2 H 3 O 2 ( aq ) ⟶NaHC2H3O2 + H2CO3 → H2O + CO2

NaHCO3 + HC2H3O2 → NaC2H3O2 + H2O + CO2

Explanation:

Sodium bicarbonate and acetic acid reacts to form Sodium acetate and carbonic acid. The carbonic acid then produce carbon dioxide gas and water after undergoing decomposition.

The complete equation for the reaction, including the phase symbols is

NaHCO₃(s) + HC₂H₃O₂(aq)  ⟶ NaC₂H₃O₂(aq) + H₂O(l) + CO₂(g)

From the question,

We are to complete the equation for the reaction of NaHCO₃(s) with HC₂H₃O₂(aq).

This is the reaction between sodium bicarbonate and acetic acid.

The complete and balanced equation for the reaction is

NaHCO₃(s) + HC₂H₃O₂(aq)  ⟶ NaC₂H₃O₂(aq) + H₂O(l) + CO₂(g)

The reaction between sodium bicarbonate and acetic acid gives sodium acetate, water and carbon dioxide gas.

Hence, the complete equation for the reaction, including the phase symbols is

NaHCO₃(s) + HC₂H₃O₂(aq)  ⟶ NaC₂H₃O₂(aq) + H₂O(l) + CO₂(g)

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