Answer:
19.8 kg of C₂H₂ is needed
Explanation:
We solve this by a rule of three:
If 1251 kJ of heat are relased in the combustion of 1 mol of acetylene
95.5×10⁴ kJ of heat may be released by the combustion of
(95.5×10⁴ kJ . 1) /1251kJ = 763.4 moles of C₂H₂
Let's convert the moles to mass → 763.4 mol . 26 g/1 mol = 19848 g
If we convert the mass from g to kg → 19848 g . 1kg / 1000g = 19.8 kg
Answer:
We need 19.88 kg of acetylene
Explanation:
Step 1: Data given
The combustion of 1 mole of acetylene releases 1251 kJ of heat
Step 2: Calculate moles acetylene needed
If we burn 1 mol, there is 1251 kJ released
If we burn x moles there is 95.5 *10^4 kJ
x = 95.5 *10^4 / 1251
x = 763.4
If we burn 763.4 moles there is 95.5 *10^4 kJ released
Step 3: Calculate mass acetylene
Mass acetylene = moles * molar mass
Mass acetylene = 763.4 moles * 26.04 g/mol
Mass acetylene = 19878.9 grams = 19.88 kg
We need 19.88 kg of acetylene
