Answer: The value of equilibrium constant, [tex]K_p[/tex] for the reaction is 0.127
Explanation:
We are given:
Partial pressure of CO at equilibrium = 0.850 atm
Partial pressure of [tex]Cl_2[/tex] at equilibrium = 1.11 atm
Partial pressure of [tex]COCl_2[/tex] at equilibrium = 0.120 atm
For the given chemical equation:
[tex]CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)[/tex]
The expression of [tex]K_p[/tex] for above equation follows:
[tex]K_p=\frac{p_{COCl_2}}{p_{CO}\times p_{Cl_2}}[/tex]
Putting values in above equation, we get:
[tex]K_p=\frac{0.120}{0.850\times 1.11}\\\\K_p=0.127[/tex]
Hence, the value of equilibrium constant, [tex]K_p[/tex] for the reaction is 0.127