Answer:
2.01 moles of P → 1.21×10²⁴ atoms
2.01 moles of N → 1.21×10²⁴ atoms
4.02 moles of Br → 2.42×10²⁴ atoms
Explanation:
We begin from this relation:
1 mol of PNBr₂ has 1 mol of P, 1 mol of N and 2 moles of Br
Then 2.01 moles of PNBr₂ will have:
2.01 moles of P
2.01 moles of N
4.02 moles of Br
To determine the number of atoms, we use the relation:
1 mol has NA (6.02×10²³) atoms
Then: 2.01 moles of P will have (2.01 . NA) = 1.21×10²⁴ atoms
2.01 moles of N (2.01 . NA) = 1.21×10²⁴ atoms
4.02 moles of Br (4.02 . NA) = 2.42×10²⁴ atoms
Answer:
For 2.01 moles PNBr2 we have 1.21 *10^24 molecules
P = 1.21 *10^24 atoms
N = 1.21 *10^24 atoms
Br = 2.42*10^24 atoms
Explanation:
Step 1: Data given
Number of moles of PNBr2 = 2.01 moles
Step 2: Calculate moles per element
For 1 mol PNBr2 we have 1 mol P, 1 mol N and 2 moles Br
For 2.01 moles PNBr2 we have:
P = 2.01 moles
N = 2.01 moles
Br = 2* 2.01 = 4.02 moles
Step 3: Calculate atoms of each element
For 2.01 moles PNBr2 we have 6.022 *10^23 * 2.01 = 1.21 *10^24 molecules
P = 2.01 moles = 6.022 *10^23 * 2.01 = 1.21 *10^24 atoms
N = 2.01 moles = 6.022 *10^23 * 2.01 = 1.21 *10^24 atoms
Br = 4.02 moles = 6.022 *10^23 * 4.02 = 2.42*10^24 atoms
