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Evaluate 5c+cd5c+cd5, c, plus, c, d when c=\dfrac15c=
5
1
​
c, equals, start fraction, 1, divided by, 5, end fraction and d=15d=15d, equals, 15.

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opudodennis

Answer:

4

Step-by-step explanation:

The function is given as 5c+cd, c=1/5 and d=15d.

We evaluate by substituting the given values of c and d in the function:

[tex]5c+cd, c=1/5 \ \ \, d=15\\\\=5\times \frac{1}{5}+\frac{1}{5}\times 15[/tex]

[tex]=1++3\\\\=4[/tex]

After substituting, we find the function's equivalent as 4.

Hence, the value of the function is 4

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