Answer:
You would use the kinematic formula:
[tex]\Delta y=V_{0y}\times t-g\times t^2/2[/tex]
Explanation:
The upwards vertical motion is ruled by the equation:
[tex]y=y_0+V_{0y}\times t-g\times t^2/2[/tex]
Where:
[tex]y \text{ is the position at the time }t:y=0.1m[/tex]
[tex]y_0\text{ is the initial position: }y_0=0[/tex]
[tex]t=2s[/tex]
[tex]g\text{ is the gravitational acceleration: }\approx 9.8m/s^2[/tex]
[tex]V_{0y}\text{ is the initial vertical velocity}[/tex]
Naming Δy = y - y₀, the equation becomes:
[tex]\Delta y=V_{0y}\times t-g\times t^2/2[/tex]
Then, you just need to substitute with Δy = 0.1m, t = 2s, and g = 9.8m/s², ans solve for the intital vertical velocity.
Answer: the equation you would use is
v = v0 +at
Explanation:
