Answer:
-5 coach tickets
-8 first class tickets
Step-by-step explanation:
let x be the number of coach tickets and y the number of first class tickets:
[tex]x+y=13\ \ \ \ \ \ ...i[/tex]
Given that coach tickets costs $260 each, and first class tickets $1080 and that the total fare budget was $9940:
[tex]260x+1080y=9940\ \ \ \ \ \ \ \ \ ...ii[/tex]
#From equation i, make x the subject of the formula:
[tex]x=13-y[/tex]
#Substitute x in ii;
[tex]260x+1080y=9940\\\\260(13-y)+1080y=9940\\\\3380-260y+1080y=9940\\\\820y=6560\\\\y=8\\\\x=13-y\\\\\therefore x=13-8=5[/tex]
Hence, Sarah bought 5 coach tickets and 8 first class tickets.