A merry-go-round accelerates from rest to 0.75 rad/s in 33 s.

Assuming the merry-go-round is a uniform disk of radius 6.0 m and mass 3.20×104 kg , calculate the net torque required to accelerate it.

Respuesta :

Answer:

1309.1 Nm

Explanation:

Torque is given as a product of Moment of innertia and acceleration hence

T=Ia where T is torque and a is acceleration

To get acceleration, it is rate of change of speed per unit time hence [tex]a=\frac {v_f-v_i}{t}[/tex] where v and t represent velocity and time respectively while subscripts f and i represent final and initial respectively. Also, I is given by [tex]0.5mr^{2}[/tex] where m js mass and r is radius hence the net torque can now be written as

[tex]T=0.5mr^{2}\times \frac {v_f-v_i}{t}[/tex]

By substituting the given figures then

[tex]T=0.5\times 3.2\times 10^{4}\times 6^{2}\times \frac {0.75-0}{33}=1309.0909090867 Nm\approx 1309.1 Nm[/tex]