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Find the slope-intercept form of an equation of the line perpendicular to the graph of x – 3y = 5 and passing through (0, 6). Question 3 options: a) y = –3x + 6 b) y = 13x − 2 c) y = 13x + 2 d) y = 3x – 6

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kylebollar

Answer:

a) y=-3x+6

Step-by-step explanation:

finding the slope of the given line:

-3y=-x+5

y=(1/3)x-(5/3)

since our new line has to be perpendicular to this line, our new line will have slope m=-3

putting these quantities into point-slope form:

y-6=-3(x-0)

converting to slope-int:

y=-3x+6

aaaamnaaah

Hello there,

Well first we need to write down what we know/what are we finding out...

 - the original line has the equation of x - 3y = 5

 - we are finding the equation of the line that is perpendicular

Now we start by changing the original equation to slope-intercept form:

  • x - 3y = 5 as slope-intercept form would be y = 1/3x -5/3

Perpendicular lines have the negative reciprocal slopes so the new line has to have the slope as -3.

Option A would be the correct answer: a) y = -3x + 6

Hope I helped,

Amna

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