Respuesta :
Answer:
Explanation:
Area of the window, A = 30 cm x 15 cm = 0.045 m²
depth, h = 1 km = 1000 m
Let P is the pressure
P = h x d x g
where d is the density of water
P = 1000 x 1000 x 9.8 = 9.8 x 10^6 Pa
Force, F = Pressure x Area
F = 9.8 x 10^6 x 0.045
F = 4.41 x 10^5 N
Answer:
[tex]F=441000\ N[/tex]
Explanation:
Given:
dimension of the window, [tex](30\times 15)\ cm[/tex]
depth of window under water, [tex]d=1000\ m[/tex]
We know that the pressure due to liquid column is given as:
[tex]P=\rho.g.d[/tex]
where:
[tex]\rho=[/tex] density of water
[tex]g=[/tex] acceleration due to gravity
[tex]d=[/tex] depth of the water column at the desired position
[tex]P=1000\times 9.8\times 1000[/tex]
[tex]P=9800000\ Pa[/tex]
Now the force acting on the area of the window:
[tex]F=P.A[/tex]
where:
[tex]A=[/tex] area of the window
[tex]F=9800000\times (0.3\times 0.15)[/tex]
[tex]F=441000\ N[/tex]
