Answer:
Perimeter: [tex]4x^2-2x+8[/tex]
Area: [tex]8x^2-4x[/tex]
Step-by-step explanation:
I will assume the question asks for perimeter and area of the rectangle with given dimensions.
The height is "4"
The width (assuming) is "[tex]2x^2-x[/tex]"
First, the perimeter:
Perimeter is sum of all 4 sides of a rectangle, so we have 2 widths and 2 lengths, we sum them up:
[tex]Perimeter=4+2x^2-x+4+2x^2-x=4x^2-2x+8[/tex]
Now, the area:
Area is the height times width, so it will be:
[tex]Area=4*(2x^2-x)=8x^2-4x[/tex]
