Answer:
2000H LXI H, 2000H memory pointer first is initialized
2003H LXI D, 2100H memory pointer second is initialized
2006H MVI C, 32H the counter, is initialized
2008H MOV A, M We achieve the number
2009H ANI 0lH We now check for an odd number
200BH JZ 2011H If it is even then never store it
200EH MOV A, M Now we achieve the number again
200FH STAX D The number is stored in the result list.
2010 H INX D Pointer 2 is incremented
2011 H INX H Pointer 1 is incremented
2012H DCR C The counter is decremented
2013H JNZ 2008H If it is not zero, then repeat it
2016H LXI H, 2000H the memory pointer 1st, is initialized
2019H LXI D, 2200H the memory pointer 2nd is initialized
201CH MVI C, 32H the counter, is initialized
201EH MOV A, M Achieve the number
201FH ANI 0lH Test whether it is even or not
2021H JNZ 2027H If it is odd, then never store it
2024H MOV A, M Achieve the number
2025H STAX D Save the number in the result list
2026H INX D Now increment the pointer number 2
2027H INX H Increment pointer number 1
2028H DCR C Counter is to be decremented
2029H JNZ 201EH If! 0 then repeat it
202CH HLT Stop
Explanation:
Please check the answer section.
