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The support at the left end of the beam will fail if the moment about A of the 15-kN force F exceeds 18 kN-m. Based on this criterion, what is the largest allowable length of the beam

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lublana

Answer:

2.4 m

Explanation:

We are given that

Maximum moment about A=18 kN m

Force=15 KN

[tex]\theta=30^{\circ}[/tex]

We have to find the largest allowable length of the beam

Let larges length of beam=L

Moment about A

M=[tex]LFsin 30=L(15)sin 30=7.5 LkN m[/tex]

According to question

[tex]M=M_{max}[/tex]

[tex]7.5 L=18[/tex]

[tex]L=\frac{18}{7.5}=2.4 m[/tex]

Hence, the largest length of the beam=2.4 m

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