Answer:
The speed with which just after he grabs her is 2.68 m/s.
Explanation:
Given that,
Mass of Erica, m = 38 m/s
Mass of Danny, m' = 46 kg
Erica reaches the high point of her bounce, Danny is moving upward past her at 4.9 m/s. At this moment, the initial speed of Erica will be 0. The momentum will remain conserved. Using the conservation of linear momentum as :
[tex]mu+m'u'=(m+m')V\\\\0+46\times 4.9=(38+46)V\\\\V=\dfrac{225.4}{84}\\\\V=2.68\ m/s[/tex]
So, the speed with which just after he grabs her is 2.68 m/s. Hence, this is the required solution.
