Answer:
The correct option is (B).
Explanation:
The Kepler's third law of motion gives the relationship between the orbital time period and the distance from the semi major axis such that,
[tex]T^2\propto a^3\\\\T^2=ka^3[/tex]
It is mentioned that, an asteroid with an orbital period of 8 years. So,
[tex](8)^2=ka^3\\\\64=ka^3\\\\a=(64)^{\dfrac{1}{3}}\\\\a=4\ AU[/tex]
So, an asteroid with an orbital period of 8 years lies at an average distance from the Sun equal to 4 astronomical units.
