Answer:
[tex]\large \boxed{\text{0.0264 mol/L; }5.0 \times 10^{-7}}[/tex]
Explanation:
1. The ICE table
[tex]\begin{array}{rccccc} &\text{Cu}\text{(IO}_{3})_{2} & \rightleftharpoons &\text{Cu}^{2+}&+ & 2\text{IO}_{3}^{-}\\\\\text{I:}& & & 0 & & 0.0250\\\text{C:}& & & +x & & x \\\text{E:}& & & x & &0.0250 + 2x\\\end{array}[/tex]
2. Concentration of IO₃⁻
At equilibrium, [Cu²⁺] = 0.000 72 mol·L⁻¹, so x = 0.000 72.
The new ICE table becomes
[tex]\begin{array}{rccccc} &\text{Cu}\text{(IO}_{3})_{2} & \rightleftharpoons &\text{Cu}^{2+}&+ & 2\text{IO}_{3}^{-}\\\\\text{I:}& & & 0 & & 0.0250\\\text{C:}& & & +0.00072 & & 0.00144 \\\text{E:}& & & 0.00072 & & \mathbf{0.0264}\\\end{array}\\\text{The equilibrium concentration of iodate ion is $\large \boxed{\textbf{0.0264 mol/L}}$}[/tex]
3. Ksp
[tex]K_{\text{sp}} = [\text{Cu}^{2+}][\text{IO}_{3}^{-}]^{2} = 0.00072 \times 0.0264^{2} = \mathbf{5.0 \times 10^{-7}}[/tex]
Answer:
0.02644 M = [IO3-]
Ksp = 0.0000005 = 5*10^-7
Explanation:
Step 1: Data given
Asaturated solution of Cu(IO3)2 was prepared in KIO3
Concentration of KIO3 = 0.0250 M
The copper concentration was found to be 0.00072 M
Step 2: Equations
Cu(IO3)2(s) + aq ⇔Cu2+(aq) + 2IO3 - (aq)
Step 3: The initial concentrations
The initial concentration of KIO3 = 0.0250 M
The initial concentration of Cu2+ is 0 M
Step 4: The changed concentrations
After preparing the Cu2+ in KIO3-; the concentration of Cu2+ will be changed with X
For every 1 Cu2+ we have 2 IO3-
This means if the concentration of Cu2+ is changed by X; the concentration of IO3- is changed by 2X. This gives a total concentration of 0.0250 + 2X for IO3-
Step 4:
Said is that the copper concentration was found to be 0.00072 M
This means the final concentration of Cu2+ is 0.00072 M or also said X = 0.00072
Now we can calculate the final IO3- concentration
0.0250 + 2X = [IO3-]
0.0250 + 2* 0.00072 = [IO3-]
0.0250 + 0.00144 = [IO3-]
0.02644 M = [IO3-]
Step 5: Calculate Ksp
Cu(IO3)2(s) ⇔Cu2++ 2IO3 -
Ksp of Cu(IO3)2 = [Cu+2]*[IO3-]²
Ksp = 0.00072 * 0.02644²
Ksp = 0.0000005 = 5*10^-7
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