Answer:
19.488 kJ
Explanation:
The overall reaction mechanism shows the reaction between LiCl and H₂O
[tex]LiCl.3H_2O ------> Li +\frac{1}{2} Cl_2+3H_2+\frac{3}{2} O_2[/tex] -------- (1)
[tex]2Li+Cl_2+10H_2O ----->LiCl.10H_2O[/tex] -------- (2)
[tex]3H_2+\frac{3}{2}O_2 -----> 3H_2O[/tex] --------- (3)
[tex]LiCl.7H_2O ------> Li + \frac{1}{2} Cl_2+7H_20[/tex] ---------- (4)
The overall reaction =
[tex]LiCl.7H_2O +LiCl.3H_2O ------> 2LiCl.10H_2O[/tex]
The heat effects of the above reactions from 1-4 respectively are in the order ; 11311.34 kJ, -857.49 kJ, -873.61 kJ and 439.288kJ respectively
The overall enthalpy change is:
[tex]\delta H = \delta H _{LiCl.3H_2O}+\delta H_{3H_2O} + \delta H_{2(LiCl.5H_2O)} + \delta H _{liCl.7H_2O}[/tex]
[tex]\delta H =Q[/tex] at constant pressure;
Thus; Q = 1311.3 (kJ) 857.49 (kJ) -873.61 (kJ) + 439.288 (kJ)
Q = 19.488 kJ
Thus, the heat effect = 19.488 kJ after the addition of 1 mol of LiCl⋅3H2O(s)
