Answer:
The minimum radius of the circle is 1892.75 meters
Explanation:
Speed of the jet, v = 1250 km/h = 347.23 m/s
We need to find the minimum radius of the circle so that the centripetal acceleration at the lowest point does not exceed 6.5 g.
The centripetal acceleration is given by :
[tex]a=\dfrac{v^2}{r}\\\\r=\dfrac{v^2}{a}\\\\r=\dfrac{(347.23)^2}{6.5\times 9.8}\\\\r=1892.75\ m[/tex]
So, the minimum radius of the circle is 1892.75 meters. Hence, this is the required solution.
