Jill and Jack both have two pails that can be used to carry water down from a hill. Each makes only one trip down the hill, and each pail of water can be sold for $5. Carrying the pails of water down requires considerable effort. Both Jill and Jack would be willing to pay $4 each to avoid carrying one pail down the hill, and an additional $4 to avoid carrying a second pail down the hill.

a. Given market prices, how many pails of water will each child fetch from the top of the hill?

pails.

b. Jill and Jack

Respuesta :

Answer:

a) Each player’s payoffs are independent of the action taken by the other. Each pail of water sells for $6. Cost of carrying on bucket is 4 and another bucket is 5. Since the cost of carrying each bucket is less than $6. Both, Jill and Jack will each carry 2 buckets.

b. Now, Jack and Jill are sharing their revenues. They will try to maximise their payoff. The payoff matrix will be as below:

Payoff Calculation:

Jack and Jill both carry 1 pail, that is, 2 pails in total:

Jack payoff= total revenue/2 – cost of carrying down the pail = $6(2)/2 - $4(1) = $2

Jill Payoff= total revenue/2 – cost of carrying down the pail = $6(2)/2 - $4(1) = $2

Jack carries 2 pails, Jill carries 1 pail, that is, 3 pails in total:

Jack payoff: total revenue/2 – (cost of carrying on the first pail + cost of carrying second pail)

= $6(3)/2 - $4(1) - $5(1) = 9 -9 =$0

Jill payoff: total revenue/2 – cost of carrying on the first pail

= $6(3)/2 - $4(1) =$5

Jack carries 1 pail, Jill carries 2 pails, that is, 3 pails in total:

Jack payoff: total revenue/2 – cost of carrying on the first pail

= $6(3)/2 - $4(1) =$5

Jill payoff: total revenue/2 – (cost of carrying on the first pail + cost of carrying second pail)

= $6(3)/2 - $4(1) - $5(1) = $0

Jack and Jill both carry 2 pails, that is, 4 pails in total:

Jack payoff: total revenue/2 – (cost of carrying on the first pail + cost of carrying second pail)

= $6(4)/2 - $4(1) - $5(1) = 12- 9 = $3

Jill payoff: total revenue/2 – (cost of carrying on the first pail + cost of carrying second pail)

= $6(4)/2 - $4(1) - $5(1) = 12- 9 = $3

This game is a like prisoners’ dilemma. Because, if Jack choose to carry 1 pail the better response from Jill is to carry 1 pail because he will get better payoff of 2. If Jack choose to carry 2 pail the better response from Jill is to carry 1 pail because he will get better payoff of 5. So, for Jill carrying 1 pail is dominant strategy.

Same ways, if Jill choose to carry 1 pail the better response from Jack is to carry 1 pail because he will get better payoff of 2. If Jill choose to carry 2 pail the better response from Jack is to carry 1 pail because he will get better payoff of 5. So, for Jack carrying 1 pail is dominant strategy.

For both Jack and Jill, the dominant strategy is to carry only one bucket down the hill.

Ver imagen hamzafarooqi188