What is the wavelength of a beam of electromagnetic radiation traveling through a vacuum with a frequency of 6 x 10^11 Hz? The speed of light in a vacuum is 3.00 x 10^8 m/s

A.) 2.0 x 10^-4m
B.) 2.0 x 10^3m
C.) 5.0 x 10^4m
D.) 5.0 x 10^-4m
E.) 5.0 x 10^-1m

Respuesta :

Answer:

Option D.) 5.0 x 10^-4m

Explanation:

Data obtained from the question include:

f (frequency) = 6 x 10^11 Hz

v (velocity) = 3.00 x 10^8 m/s

λ (wavelength) =?

Using the equation v = λf, the wavelength can be obtained as illustrated below:

v = λf

λ = v/f

λ = 3.00 x 10^8/6 x 10^11

λ = 5 x 10^-4m

Therefore, the wavelength of the beam of the electromagnetic radiation is 5 x 10^-4m