Answer:
A drink costs $4.50 and a bag of popcorn costs $5.00.
Step-by-step explanation:
The system would be:
[tex]6d+6p=57\\4d+3p=33\\[/tex]
I'll be using the subtraction method first, to find d (price of a drink):
[tex]+6d+6p=+57\\-8d-6p=-66\\--------\\-2d=-9\\\\2d=9\\d=4.5[/tex]
Now, we substitute in and solve for p:
[tex]6(4.5)+6p=57\\27+6p=57\\6p=30\\p=5[/tex]
Finally, we use the second equation to check the values:
[tex]4(4.5)+3(5)=33\\18+15=33\\33=33[/tex]
So:
[tex]\left \{ {{d=4.5} \atop {p=5}} \right.[/tex]
