Answer with Explanation:
We are given that
Mass,m=11.5 kg
[tex]v_x=75 cm/s=0.75 m/s,v_y=0[/tex]
1 m=100 cm
[tex]m'=1.25 kg[/tex]
[tex]v'_x=0,v'_y=3.6 m/s[/tex]
According to law of conservation momentum along east west direction
[tex]11.5\times 0.75+1.25(0)=(11.5+1.25)V_x[/tex]
[tex]8.625=12.75V_x[/tex]
[tex]V_x=\frac{8.625}{12.75}[/tex]
[tex]V_x=0.68 m/s[/tex]
According to law of conservation of momentum along north south direction
[tex]11.5(0)+1.25(3.6)=(11.5+1.25)V_y[/tex]
[tex]4.5=12.75V_y[/tex]
[tex]V_y=\frac{4.5}{12.75}=0.35 m/s[/tex]
[tex]V=\sqrt{V^2_x+V^2_y}[/tex]
[tex]V=\sqrt{(0.68)^2+(0.35)^2}[/tex]
[tex]V=0.76 m/s[/tex]
Direction,[tex]\theta=tan^{-1}(\frac{V_y}{V_x})[/tex]
[tex]\theta=tan^{-1}(\frac{0.35}{0.68})[/tex]
[tex]\theta=27.23^{\circ}[/tex]
