Answer:
2.4moles
Explanation:
Number of moles of Cl₂ = 2.50moles
Number of moles of F₂ = 6.15moles
Unknown:
Moles of excess reactant left = ?
Solution:
The reaction equation:
Cl₂ + 3F₂ → 2ClF₃
Now, we need to find the excess reactant;
2 mole of chlorine gas combined with 3 mole of fluorine gas;
2.5 moles of chlorine gas will combine with [tex]\frac{2.5 x 3}{2}[/tex] = 3.75moles of F₂
The given number of moles of F₂ is 6.15moles
But the reaction needs 3.75 moles
The amount of excess reactant left = 6.15 - 3.75 = 2.4moles
