Answer:
90g
Explanation:
Let us write a balanced equation for the reaction. NaHCO3 decompose to yield water as illustrated below:
2NaHCO3—> Na2CO3 + CO2 + H2O
Theoretical yield of water can be obtained as follow:
From the equation,
2 moles of NaHCO3 produced 1 mole of H2O.
Therefore, 10 mole of NaHCO3 will produce = 10/2 = 5 moles of H2O.
Now we shall convert 10 moles of H2O to grams to obtain the theoretical yield of water. This is illustrated below:
Molar Mass of H2O = (2x1) + 16 = 2 + 16 = 18g/mol
Number of mole of H2O = 5 moles
Mass of H2O =?
Mass = number of mole x molar Mass
Mass of H2O = 5 x 18
Mass of H2O = 90g.
Therefore, the theoretical yield of water is 90g
