what is the area of this figure?

Answer:
114.8 cm^2
Step-by-step explanation:
we can break down this figure into individual shapes :
- rectangle
- triangle
- parallelogram
formula:
[tex]\frac{1}{2} * base * height\\[/tex]
[tex]\frac{1}{2} * 11.2 * 4.5\\[/tex]
area of a triangle =25.2 cm^2
formula:
[tex]base * height\\[/tex]
4.5 * 8
area of a rectangle = 36 cm^2
formula:
1/2 * ( sum of parallel sides ) * height
1/2 * ( 8 + 8 ) * 6.7
area of a parallelogram = 53.6 cm^2
= area of rectangle + area of triangle + area of parallelogram
= 25.2 + 36 + 53.6
The area of the given figure is 114.8 sq cm.
Step-by-step explanation:
Given,
The figure consists of a right angle triangle, a rectangle and a parallelogram
Area of the fig = area of triangle + area of rectangle + area of parallelogram
For the triangle
Height (h) = 4.5 cm
Base (b) = 11.2 cm
For the rectangle
Length (l) = 8 cm
Width (w) = 4.5 cm
For the parallelogram
Length of opposite parallel side (b) = 8 cm
Height (h) = 6.7 cm
To find the area of the figure.
Formula
Area of triangle = [tex]\frac{1}{2}[/tex]×b×h
Area of rectangle = l×w
Area of parallelogram = b×h
Now,
Area of triangle = [tex]\frac{1}{2}[/tex]×11.2×4.5 sq cm
=25.2 sq cm
Area of rectangle = 8×4.5 sq cm = 36 sq cm
Area of parallelogram = 6.7×8 sq cm = 53.6 sq cm
Hence,
Area of the fig = 25.2+36+53.6 sq cm = 114.8 sq cm