Answer:
[tex]\mu=7.5\\\\\sigma=2.3\\[/tex]
Step-by-step explanation:
We know that 30% of all students who have to buy a text for a particular course want a newcopy, whereas the other 70% want a used copy. So, we get that:
p=30%=0.3
q=70%=0.7
n=25.
We calculate the mean:
[tex]\mu=E(X)=n\cdot p=25\cdot 0.3=7.5[/tex]
We calculate the standard deviation:
[tex]\sigma=\sqrt{p\cdot q\cdot n}=\sqrt{0.3\cdot 0.7\cdot 25}=\sqrt{5.25}=2.3\\[/tex]
We get that the mean and standard deviation are:
[tex]\mu=7.5\\\\\sigma=2.3\\[/tex]