Answer:
[tex]\{e^{11x},e^{-5x}\}[/tex]
Step-by-step explanation:
We have the differential operator
[tex]D^{2}-6D-55[/tex]
the factors are
[tex](D-11)(D+5)[/tex]
we also know that for any operator of the form (D - α) the function that is annulated by the operator has the form:
[tex](D-\alpha)^{n} --> x^{n-1}e^{\alpha x}[/tex]
in our case we have n=1 and α=11,-5. Hence we have
[tex](D-11) --> e^{11x}\\(D-(-5)) --> e^{-5x}[/tex]
the solutions are
[tex]\{e^{11x},e^{-5x}\}[/tex]
I hope this is useful for you
regards