Answer:
The percent increase in iron is 50 %.
Step-by-step explanation:
The percentage increase is given by
Firstly we find the increase or the difference in the amount of iron per serving as follows
Increase in iron per serving = Final iron content - Initial iron content
= 1.8 mg of iron - 1.2 mg of iron= 0.6 mg of iron
Next, we divide the increase by the initial or original iron content which is
1.2 mg of iron per serving
Hence [tex]\frac{Increase \hspace{0.05cm} in \hspace{0.05cm} iron \hspace{0.05cm} per \hspace{0.05cm} serving}{Initial \hspace{0.05cm} iron \hspace{0.05cm} content} = \frac{0.6 \hspace{0.05cm} mg}{1.2\hspace{0.05cm} mg} = 0.5[/tex]
Next, we multiply by 100 to get the value as a percentage,
That is 0.5 × 100 = 50 %
The percent increase in iron = 50 %.
